Create my own exam Math Problem Example | Topics and Well Written Essays - 750 words

Create my own exam - Math Problem Example A line passing through the centre of a circle is the diameter of the circle (Mosteller 109). If two or more diameters are in the same circle then all of them are equal in length irrespective of their position. Therefore, if the two sides from both triangles that pass through the middle of the circle were taken as o for Triangle A and x for triangle B, then o will be equal to x. The side will also be the longest on either triangle. In the equation o + p + q = x + y + z we can eliminate o and x since they cancel each other keeping in mind that o = x, hence we will be left to prove that p + q = y + z. To prove this we will first have to identify the angles formed by the two triangles. If triangle A has angles O, P, Q where angle P and Q join sides p and q to side o respectively, then angle O is opposite to side o. On the other hand, triangle B has angles X, Y, Z where by angle X is opposite to side x and angles Y and Z join sides y and z to side x respectively. If we start with both tri angles as isosceles triangles then sides p + q = y + z because for both triangles the longer side is equal (Kac and Ulam 167). In the event that the shape of either triangle changes then the following, changes will also take place. Let us start with triangle A, a change in the shape of the triangle from an isosceles triangle an irregular triangle this will cause angle O to increase. The change will also be associated with change in length of side p and q, where with every increase in side p side q will be subsequently decreasing and vice versa. The total length of the two sides will be maintained that is p + q for all the changes will remain the same. In triangle B the same principle will also apply such that a change in the shape of the triangle from an isosceles triangle to an irregular triangle then angle X will be increasing and an increase in side y will lead to a decrease in side z and vice versa. The total length in this case will be maintained that is to say that y + z will remain the same in whichever shape the triangle changes. Since p + q = y + z for the isosceles triangle then the same principle will apply for a change in shape of the triangles. Theorem 2 If a rectangle is drawn inside a chessboard with its sides parallel to the sides of the chessboard, then the number of complete dark squares will NOT be equal to the number of light squares covered by the rectangle. That is if the rectangle covers m complete dark squares and n complete light squares then m ? n. Taking note that not necessarily that all the squares covered by the rectangle will be complete. Proof: Suppose we take a chessboard (which is square in shape) with sides C and D where C = D and inside the chessboard there are ‘n’ equal squares, which are made of one unit of each side, therefore n = C ? D (Garder 510). The dark squares are denoted by b and the light squares denoted as w. A rectangle with length J and width K is drawn inside the chessboard where the side J is pa rallel to C and K is parallel to D. Further, J should not be equal to C and K should not be equal to D, meaning the rectangle is smaller than the chessboard and there should be no three sides of the rectangle touching the sides of the chessboard. If the rectangle is drawn to fit exactly two units of C and one unit of D then the rectangle will

First assist surgical study Case Example | Topics and Well Written Essays - 1250 words

First assist surgical - Case Study Example It involves cutting the linking parts and then conducting a usual vaginal surgery to take away specimen from the body. 1. Organ Structure function: The ovaries are two glands that are a constituent of the female reproductive system and are responsible for production of ova. Each of them is oval in shape and almost equal to the almond in size. They are found near the fallopian tubes in the tangential wall of the pelvis in an enclosure referred to as ovarian fossa. Each of the ovaries is connected to the fimbria of the fallopian tube. Three incisions will be made. These can be seen by the patient. The first one is to accommodate the telescope and is within or close to the navel. The other cuts are done in the lower part of the abdomen. These are 5mm long while the first is 1 cm in length (Petri et al. 170). Another slit is done at the top of the vagina to remove the needed material for analysis. The patient will wake up in the recovery room after the procedure and after the effects of the anaesthetic diminish. Some patients might require an oxygen mask to assist in the inhalation of oxygen ((Querleu, Leblanc and Castelain 580). Lukanovic, A; Drazic, K (2010). "Risk factors for vaginal prolapse after hysterectomy". International journal of gynaecology and obstetrics: the official organ of the International Federation of Gynaecology and Obstetrics 110 (1): 27–30. Petri Nahà ¡s, E.; Pontes, A.; Nahas-Neto, J.; Borges, V.; Dias, R.; Traiman, P. (2005). "Effect of total abdominal hysterectomy on ovarian blood supply in women of reproductive age". Journal of ultrasound in medicine  : official journal of the American Institute of Ultrasound in Medicine 24 (2):